What will happen while running the following code?

public class Test implements Runnable {
    public static void main(String[] args) {
        Thread t = new Thread(this);
        try {
            t.start();
        } catch (IOException ioe) {
            System.out.println("IOException");
        }
    }

    public void run() throws IOException {
        File f = new File("file.txt");
        FileWriter fw = new FileWriter(f);
    }
}
Explanation
1. this is not accessible from static methods.
2. IOException is checked exception. Thread.start() is not declared with throws IOException, therefore throwing IOException in catch-block will cause a compilation error.
3. Method run in Runnable is declared as public abstract void run() without throws clause. Therefore classes that implement this interface can't add any throws clause to the declaration of this method.

Следи за CodeGalaxy

Мобильное приложение Beta

Get it on Google Play
Обратная Связь
Продолжайте изучать
тесты по Java
Cosmo
Зарегистрируйся сейчас
или Подпишись на будущие тесты