Что произойдет при компиляции и выполнении данного

Что произойдет при компиляции и выполнении данного класса?


public class VerySimpleClass {
  public static void main(String... args) {
     for (byte i = 1, j = 0; (j += i++) <= 10; i = 1, System.out.print(--j));
  }
}

Explanation

Code will be compiled successfully since given form of the for loop is syntactically correct and does not contain errors. However, the program will fall into an infinite loop, because the value of the j is not growing and at the point of loop continuation condition check the variable j will always be equal to 1.