What will be printed as a result of the following

What will be printed as a result of the following program:

#include <iostream>

void f() {
     throw 10;
}

int main() {
    try {
        f();
    } catch (...) {
        std::cout << "all ";
    } catch (double) {
        std::cout << "double ";
    } catch (int) {
        std::cout << "int ";
    }
    return 0;
}

Explanation

The catch(...) block {/*....*/} must be the last in the series of exception traps. Standard 15.3.6 Otherwise, this block will always be controlled if an exception occurs, regardless of whether there is a more suitable processing block for the excited exception or not (in this case, if there was no compilation error, catch(int) would be skipped).