What will be printed during execution:


#include <iostream>

int main()
{
    int x[] = {3,5,8} ;
    std::cout << (*x)["my string"+3] ;
}

Explanation

Will be printed "i".
Dereferencing of "x" will give the value "x[0] == 3".
"my string" will be converted to a const pointer to a given string.
We will get the following: 3[pointer+3]
This expression, according to the language rules, will be converted to *(3+pointer+3).
Thereby in brackets, we will get the offset on 6 symbols in the string "my string" and while dereferencing will get const char with value "i"