What will be the output of the following code:

#include <iostream>

int foo ( int & x )
    return x*3 ;

int foo ( int x )
    return x*2 ;

int main()
    int intvar = 3 ;
    float floatvar = 10.84 ;
    std::cout << foo(2+intvar) << foo(floatvar) ;
In both cases a temporary variable of type const int will be created.
The C++ standard prohibits modification of temporary variables, hence the first function will be omitted in both cases. The second function will create a copy of the passed in variable, hence, it will be called in both cases.

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