What is the result of the following code execution?

public class BooleanTest {
   static boolean test1(int val) {
        System.out.println("test1("+ val +")");
        System.out.println("result: " + (val < 10));
        return val < 10;
    }

    static boolean test2(int val) {
        System.out.println("test2("+ val +")");
        System.out.println("result: " + (val < 20));
        return val < 20;
    }

    static boolean test3(int val) {
        System.out.println("test3("+ val +")");
        System.out.println("result: " + (val < 30));
        return val < 30;
    }

    public static void main(String[] args) {
       if(test1(0) && test2(20) && test3(20))
           System.out.println("Expression is true");
       else
           System.out.println("Expression is false");
    }
}
Explanation
&& operator evaluates the operands in order from left to right until it can unequivocally determine the truth of the whole expression.
Therefore, in this example, only two methods are called:
test1(0) – true
test2(20) – false
There is no sense to call test3() method, because regardless of its result, it is clear that the value of the entire expression is false.

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